Find the best tutors and institutes for Class 12 Tuition
Search in
For what value of 
is the function defined by
continuous at x = 0? What about continuity at x = 1?
The given function f is
If f is continuous at x = 0, then
Therefore, there is no value of λ for which f is continuous at x = 0
At x = 1,
f (1) = 4x + 1 = 4 × 1 + 1 = 5
Therefore, for any values of λ, f is continuous at x = 1
Find the values of k so that the function f is continuous at the indicated point.
The given function f is
The given function f is continuous at x = 5, if f is defined at x = 5 and if the value of f at x = 5 equals the limit of f at x = 5
At x=5 LHL is K x 5+1 = 5K+1 and RHL is 3 x 5-5=10
Since the fungtion is contiuous at x=5 , LHL=RHL
Hence, 5K+1=10 and 
Therefore, the required value of
Examine that 
is a continuous function.
This function f is defined for every real number and f can be written as the composition of two functions as,
f = g o h, where
It has to be proved first that are continuous functions.
Clearly, g is defined for all real numbers.
Let c be a real number.
Case I:
Therefore, g is continuous at all points x, such that x < 0
Case II:
Therefore, g is continuous at all points x, such that x > 0
Case III:
Therefore, g is continuous at x = 0
From the above three observations, it can be concluded that g is continuous at all points.
h (x) = sin x
It is evident that h (x) = sin x is defined for every real number.
Let c be a real number. Put x = c + k
If x → c, then k → 0
h (c) = sin c
Therefore, h is a continuous function.
It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c.
Therefore, 
is a continuous function.
Prove that the function
is continuous at
Therefore, f is continuous at x = 0
Therefore, f is continuous at x = −3
Therefore, f is continuous at x = 5
Examine the following functions for continuity.
(a) 
(b) 
(c) 
(d) 
(a) The given function is
It is evident that f is defined at every real number k and its value at k is k − 5.
It is also observed that, 
Hence, f is continuous at every real number and therefore, it is a continuous function.
(b) The given function is
For any real number k ≠ 5, we obtain
Hence, f is continuous at every point in the domain of f and therefore, it is a continuous function.
(c) The given function is
For any real number c ≠ −5, we obtain
Hence, f is continuous at every point in the domain of f and therefore, it is a continuous function.
(d) The given function is 
This function f is defined at all points of the real line.
Let c be a point on a real line. Then, c < 5 or c = 5 or c > 5
Case I: c < 5
Then, f (c) = 5 − c
Therefore, f is continuous at all real numbers less than 5.
Case II : c = 5
Then, 
Therefore, f is continuous at x = 5
Case III: c > 5
Therefore, f is continuous at all real numbers greater than 5.
Hence, f is continuous at every real number and therefore, it is a continuous function.
Prove that the function 
is continuous at x = n, where n is a positive integer.
The given function is f (x) = xn
It is evident that f is defined at all positive integers, n, and its value at n is nn.
Therefore, f is continuous at n, where n is a positive integer.
Is the function f defined by
continuous at x = 0? At x = 1? At x = 2?
The given function f is
At x = 0,
It is evident that f is defined at 0 and its value at 0 is 0.
Therefore, f is continuous at x = 0
At x = 1,
f is defined at 1 and its value at 1 is 1.
The left hand limit of f at x = 1 is,
The right hand limit of f at x = 1 is,
Therefore, f is not continuous at x = 1
At x = 2,
f is defined at 2 and its value at 2 is 5.
Therefore, f is continuous at x = 2
Find all points of discontinuity of f, where f is defined by
The given function f is
It is evident that the given function f is defined at all the points of the real line.
Let c be a point on the real line. Then, three cases arise.
(i) c < 2
(ii) c > 2
(iii) c = 2
Case (i) c < 2
Therefore, f is continuous at all points x, such that x < 2
Case (ii) c > 2
Therefore, f is continuous at all points x, such that x > 2
Case (iii) c = 2
Then, the left hand limit of f at x = 2 is,
The right hand limit of f at x = 2 is,
It is observed that the left and right hand limit of f at x = 2 do not coincide.
Therefore, f is not continuous at x = 2
Hence, x = 2 is the only point of discontinuity of f.
Find all points of discontinuity of f, where f is defined by
The given function f is
The given function f is defined at all the points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x, such that x < −3
Case II:
Therefore, f is continuous at x = −3
Case III:
Therefore, f is continuous in (−3, 3).
Case IV:
If c = 3, then the left hand limit of f at x = 3 is,
The right hand limit of f at x = 3 is,
It is observed that the left and right hand limit of f at x = 3 do not coincide.
Therefore, f is not continuous at x = 3
Case V:
Therefore, f is continuous at all points x, such that x > 3
Hence, x = 3 is the only point of discontinuity of f.
Find all points of discontinuity of f, where f is defined by
The given function f is
It is known that,
Therefore, the given function can be rewritten as
The given function f is defined at all the points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x < 0
Case II:
If c = 0, then the left hand limit of f at x = 0 is,
The right hand limit of f at x = 0 is,
It is observed that the left and right hand limit of f at x = 0 do not coincide.
Therefore, f is not continuous at x = 0
Case III:
Therefore, f is continuous at all points x, such that x > 0
Hence, x = 0 is the only point of discontinuity of f.
Find all points of discontinuity of f, where f is defined by
The given function f is
It is known that,
Therefore, the given function can be rewritten as
Let c be any real number. Then, 
Also,
Therefore, the given function is a continuous function.
Hence, the given function has no point of discontinuity.
Find all points of discontinuity of f, where f is defined by
The given function f is
The given function f is defined at all the points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x, such that x < 1
Case II:
The left hand limit of f at x = 1 is,
The right hand limit of f at x = 1 is,
Therefore, f is continuous at x = 1
Case III:
Therefore, f is continuous at all points x, such that x > 1
Hence, the given function f has no point of discontinuity.
Find all points of discontinuity of f, where f is defined by
The given function f is
The given function f is defined at all the points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x, such that x < 2
Case II:
Therefore, f is continuous at x = 2
Case III:
Therefore, f is continuous at all points x, such that x > 2
Thus, the given function f is continuous at every point on the real line.
Hence, f has no point of discontinuity.
Find all points of discontinuity of f, where f is defined by
The given function f is
The given function f is defined at all the points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x, such that x < 1
Case II:
If c = 1, then the left hand limit of f at x = 1 is,
The right hand limit of f at x = 1 is,
It is observed that the left and right hand limit of f at x = 1 do not coincide.
Therefore, f is not continuous at x = 1
Case III:
Therefore, f is continuous at all points x, such that x > 1
Thus, from the above observation, it can be concluded that x = 1 is the only point of discontinuity of f.
Is the function defined by
a continuous function?
The given function is
The given function f is defined at all the points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x, such that x < 1
Case II:
The left hand limit of f at x = 1 is,
The right hand limit of f at x = 1 is,
It is observed that the left and right hand limit of f at x = 1 do not coincide.
Therefore, f is not continuous at x = 1
Case III:
Therefore, f is continuous at all points x, such that x > 1
Thus, from the above observation, it can be concluded that x = 1 is the only point of discontinuity of f.
Discuss the continuity of the function f, where f is defined by
The given function is
The given function is defined at all points of the interval [0, 10].
Let c be a point in the interval [0, 10].
Case I:
Therefore, f is continuous in the interval [0, 1).
Case II:
The left hand limit of f at x = 1 is,
The right hand limit of f at x = 1 is,
It is observed that the left and right hand limits of f at x = 1 do not coincide.
Therefore, f is not continuous at x = 1
Case III:
Therefore, f is continuous at all points of the interval (1, 3).
Case IV:
The left hand limit of f at x = 3 is,
The right hand limit of f at x = 3 is,
It is observed that the left and right hand limits of f at x = 3 do not coincide.
Therefore, f is not continuous at x = 3
Case V:
Therefore, f is continuous at all points of the interval (3, 10].
Hence, f is not continuous at x = 1 and x = 3
Discuss the continuity of the function f, where f is defined by
The given function is
The given function is defined at all points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x, such that x < 0
Case II:
The left hand limit of f at x = 0 is,
The right hand limit of f at x = 0 is,
Therefore, f is continuous at x = 0
Case III:
Therefore, f is continuous at all points of the interval (0, 1).
Case IV:
The left hand limit of f at x = 1 is,
The right hand limit of f at x = 1 is,
It is observed that the left and right hand limits of f at x = 1 do not coincide.
Therefore, f is not continuous at x = 1
Case V:
Therefore, f is continuous at all points x, such that x > 1
Hence, f is not continuous only at x = 1
Discuss the continuity of the function f, where f is defined by
The given function f is
The given function is defined at all points of the real line.
Let c be a point on the real line.
Case I:
Therefore, f is continuous at all points x, such that x < −1
Case II:
The left hand limit of f at x = −1 is,
The right hand limit of f at x = −1 is,
Therefore, f is continuous at x = −1
Case III:
Therefore, f is continuous at all points of the interval (−1, 1).
Case IV:
The left hand limit of f at x = 1 is,
The right hand limit of f at x = 1 is,
Therefore, f is continuous at x = 2
Case V:
Therefore, f is continuous at all points x, such that x > 1
Thus, from the above observations, it can be concluded that f is continuous at all points of the real line.
Find the relationship between a and b so that the function f defined by
is continuous at x = 3.
The given function f is
If f is continuous at x = 3, then
Therefore, from (1), we obtain
Therefore, the required relationship is given by,
Show that the function defined by 
is discontinuous at all integral point. Here 
denotes the greatest integer less than or equal to x.
The given function is
It is evident that g is defined at all integral points.
Let n be an integer.
Then,
The left hand limit of f at x = n is,
The right hand limit of f at x = n is,
It is observed that the left and right hand limits of f at x = n do not coincide.
Therefore, f is not continuous at x = n
Hence, g is discontinuous at all integral points.
Is the function defined by 
continuous at x = π?
The given function is
It is evident that f is defined at x = ππ.
Therefore, the given function f is continuous at x = π
Discuss the continuity of the following functions.
(a) f (x) = sin x + cos x
(b) f (x) = sin x − cos x
(c) f (x) = sin x × cos x
It is known that if g and h are two continuous functions, then
are also continuous.
It has to proved first that g (x) = sin x and h (x) = cos x are continuous functions.
Let g (x) = sin x
It is evident that g (x) = sin x is defined for every real number.
Let c be a real number. Put x = c + h
If x → c, then h → 0
Therefore, g is a continuous function.
Let h (x) = cos x
It is evident that h (x) = cos x is defined for every real number.
Let c be a real number. Put x = c + h
If x → c, then h → 0
h (c) = cos c
Therefore, h is a continuous function.
Therefore, it can be concluded that
(a) f (x) = g (x) + h (x) = sin x + cos x is a continuous function
(b) f (x) = g (x) − h (x) = sin x − cos x is a continuous function
(c) f (x) = g (x) × h (x) = sin x × cos x is a continuous function
Discuss the continuity of the cosine, cosecant, secant and cotangent functions,
It is known that if g and h are two continuous functions, then
It has to be proved first that g (x) = sin x and h (x) = cos x are continuous functions.
Let g (x) = sin x
It is evident that g (x) = sin x is defined for every real number.
Let c be a real number. Put x = c + h
If x 
c, then h 0
Therefore, g is a continuous function.
Let h (x) = cos x
It is evident that h (x) = cos x is defined for every real number.
Let c be a real number. Put x = c + h
If x ® c, then h ® 0
h (c) = cos c
Therefore, h (x) = cos x is continuous function.
It can be concluded that,
Therefore, cosecant is continuous except at x = np, n Î Z
Therefore, secant is continuous except at 
Therefore, cotangent is continuous except at x = np, n Î Z
Find the points of discontinuity of f, where
The given function f is
It is evident that f is defined at all points of the real line.
Let c be a real number.
Case I:
Therefore, f is continuous at all points x, such that x < 0
Case II:
Therefore, f is continuous at all points x, such that x > 0
Case III:
The left hand limit of f at x = 0 is,
The right hand limit of f at x = 0 is,
Therefore, f is continuous at x = 0
From the above observations, it can be concluded that f is continuous at all points of the real line.
Thus, f has no point of discontinuity.
Determine if f defined by
is a continuous function?
The given function f is
It is evident that f is defined at all points of the real line.
Let c be a real number.
Case I:
Therefore, f is continuous at all points x ≠ 0
Case II:
.png)
⇒−x2≤x2sin1x≤x2⇒-x2≤x2sin1x≤x2.png)
Therefore, f is continuous at x = 0
From the above observations, it can be concluded that f is continuous at every point of the real line.
Thus, f is a continuous function.
Examine the continuity of f, where f is defined by
The given function f is
It is evident that f is defined at all points of the real line.
Let c be a real number.
Case I:
Therefore, f is continuous at all points x, such that x ≠ 0
Case II:
Therefore, f is continuous at x = 0
From the above observations, it can be concluded that f is continuous at every point of the real line.
Thus, f is a continuous function.
Find the values of k so that the function f is continuous at the indicated point.
The given function f is
The given function f is continuous at
, if f is defined at and if the value of the f at equals the limit of f at.
It is evident that f is defined at and
Therefore, the required value of k is 6.
Find the values of k so that the function f is continuous at the indicated point.
The given function is
The given function f is continuous at x = 2, if f is defined at x = 2 and if the value of f at x = 2 equals the limit of f at x = 2
It is evident that f is defined at x = 2 and
Therefore, the required value of
.
Find the values of k so that the function f is continuous at the indicated point.
The given function is
The given function f is continuous at x = p, if f is defined at x = p and if the value of f at x = p equals the limit of f at x = p
It is evident that f is defined at x = p and
Therefore, the required value of
Find the values of a and b such that the function defined by
is a continuous function.
The given function f is
It is evident that the given function f is defined at all points of the real line.
If f is a continuous function, then f is continuous at all real numbers.
In particular, f is continuous at x = 2 and x = 10
Since f is continuous at x = 2, we obtain
Since f is continuous at x = 10, we obtain
On subtracting equation (1) from equation (2), we obtain
8a = 16
⇒ a = 2
By putting a = 2 in equation (1), we obtain
2 × 2 + b = 5
⇒ 4 + b = 5
⇒ b = 1
Therefore, the values of a and b for which f is a continuous function are 2 and 1 respectively.
Show that the function defined by f (x) = cos (x2) is a continuous function.
The given function is f (x) = cos (x2)
This function f is defined for every real number and f can be written as the composition of two functions as,
f = g o h, where g (x) = cos x and h (x) = x2
It has to be first proved that g (x) = cos x and h (x) = x2 are continuous functions.
It is evident that g is defined for every real number.
Let c be a real number.
Then, g (c) = cos c
Therefore, g (x) = cos x is continuous function.
h (x) = x2
Clearly, h is defined for every real number.
Let k be a real number, then h (k) = k2
Therefore, h is a continuous function.
It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c.
Therefore, 
is a continuous function.
Show that the function defined by
is a continuous function.
The given function is
This function f is defined for every real number and f can be written as the composition of two functions as,
f = g o h, where
It has to be first proved that are continuous functions.
Clearly, g is defined for all real numbers.
Let c be a real number.
Case I:
Therefore, g is continuous at all points x, such that x < 0
Case II:
Therefore, g is continuous at all points x, such that x > 0
Case III:
Therefore, g is continuous at x = 0
From the above three observations, it can be concluded that g is continuous at all points.
h (x) = cos x
It is evident that h (x) = cos x is defined for every real number.
Let c be a real number. Put x = c + h
If x → c, then h → 0
h (c) = cos c
Therefore, h (x) = cos x is a continuous function.
It is known that for real valued functions g and h,such that (g o h) is defined at c, if g is continuous at c and if f is continuous at g (c), then (f o g) is continuous at c.
Therefore, 
is a continuous function.
Find all the points of discontinuity of f defined by
.
The given function is
The two functions, g and h, are defined as
Then, f = g − h
The continuity of g and h is examined first.
Clearly, g is defined for all real numbers.
Let c be a real number.
Case I:
Therefore, g is continuous at all points x, such that x < 0
Case II:
Therefore, g is continuous at all points x, such that x > 0
Case III:
Therefore, g is continuous at x = 0
From the above three observations, it can be concluded that g is continuous at all points.
Clearly, h is defined for every real number.
Let c be a real number.
Case I:
Therefore, h is continuous at all points x, such that x < −1
Case II:
Therefore, h is continuous at all points x, such that x > −1
Case III:
Therefore, h is continuous at x = −1
From the above three observations, it can be concluded that h is continuous at all points of the real line.
g and h are continuous functions. Therefore, f = g − h is also a continuous function.
Therefore, f has no point of discontinuity.
How helpful was it?
How can we Improve it?
Please tell us how it changed your life *
Please enter your feedback
UrbanPro.com helps you to connect with the best Class 12 Tuition in India. Post Your Requirement today and get connected.
Find best tutors for Class 12 Tuition Classes by posting a requirement.
Get started now, by booking a Free Demo Class
. 
