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Redox Reactions

Redox Reactions relates to CBSE/Class 11/Science/Chemistry

Top Tutors who teach Redox Reactions

1
Satara, Satara
8 yrs of Exp
800per hour
Classes: Class 11 Tuition, Class 12 Tuition

I am a teacher. My total teaching experience is 8 years. I teach for classes 11th and 12th as well as NEET / JEE Main. I am working in a reputed institute...

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Koshal A. Class 11 Tuition trainer in Delhi Featured
Uttam Nagar Param Puri, Delhi
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10 yrs of Exp
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I am a chemistry teacher 1. Name: amit gupta 2 .Teaching subjects *chemistry* Xi-xii , jee, neet *experience of teaching of students of following...

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Mandawali, Delhi
11 yrs of Exp
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Electricity Board Area Kota Thermal Power Station Colony, Kota
8 yrs of Exp
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Prem Nagar, Hisar
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I've been passionately teaching chemistry for class 11th, 12th, JEE Mains, and NEET UG for the past 10 years. Armed with an MSc in Chemistry, my mission...

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10
Ankita J. Class 11 Tuition trainer in Udaipur Featured
Hiran Magri Sector 14, Udaipur
Super Tutor
5 yrs of Exp
300per hour
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I am a home tutor I teach since 2016. my teaching style is easy and impactful I use examples and mostly I use the questioner method mostly I used...

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Redox Reactions Questions

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Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Redox Reactions

Sadika

Oxidation Numbers and Structures: H2SO5: The sum of oxidation numbers in a neutral compound is 0. Since hydrogen has an oxidation state of +1 and oxygen usually has an oxidation state of -2, we can set up the equation: 2x+(−2×5)=02x+(−2×5)=0. Solving for xx, we get x=+5x=+5.... read more

 

  • Oxidation Numbers and Structures:

    • H2SO5: The sum of oxidation numbers in a neutral compound is 0. Since hydrogen has an oxidation state of +1 and oxygen usually has an oxidation state of -2, we can set up the equation: 2x+(−2×5)=02x+(−2×5)=0. Solving for xx, we get x=+5x=+5. Therefore, sulfur has an oxidation state of +5 in H2SO5. The structure of H2SO5 can be suggested as a peroxysulfuric acid, also known as persulfuric acid (H2SO5H2SO5).
    • Cr2O2: The sum of oxidation numbers in a neutral compound is 0. Considering oxygen usually has an oxidation state of -2, we can set up the equation: (2×x)+(2×(−2))=0(2×x)+(2×(−2))=0. Solving for xx, we get x=+2x=+2. Therefore, chromium has an oxidation state of +2 in Cr2O2. However, the compound Cr2O2 does not exist. A possible fallacy in the compound name could be due to misrepresentation or an incorrectly written chemical formula.
    • NOT: The term "NOT" does not correspond to a known chemical compound. Therefore, no oxidation numbers or structures can be assigned.

 

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Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Redox Reactions

Sadika

Formulas for Compounds: (a) Mercury (II) chloride: HgCl2HgCl2 (b) Nickel (II) sulphate: NiSO4NiSO4 (c) Tin (IV) oxide: SnO2SnO2 (d) Thallium: Thallium can form various compounds, so a specific formula cannot be given without additional information. read more

 

  • Formulas for Compounds:

    • (a) Mercury (II) chloride: HgCl2HgCl2
    • (b) Nickel (II) sulphate: NiSO4NiSO4
    • (c) Tin (IV) oxide: SnO2SnO2
    • (d) Thallium: Thallium can form various compounds, so a specific formula cannot be given without additional information.

 

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Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Redox Reactions

Sadika

Substances with Variable Oxidation States for Carbon and Nitrogen: Carbon: Carbon can exhibit oxidation states from -4 to +4 in compounds such as methane (CH4CH4), carbon monoxide (COCO), carbon dioxide (CO2CO2), and formaldehyde (H2COH2CO). Nitrogen: Nitrogen can exhibit oxidation states from -3... read more

 

  • Substances with Variable Oxidation States for Carbon and Nitrogen:

    • Carbon: Carbon can exhibit oxidation states from -4 to +4 in compounds such as methane (CH4CH4), carbon monoxide (COCO), carbon dioxide (CO2CO2), and formaldehyde (H2COH2CO).
    • Nitrogen: Nitrogen can exhibit oxidation states from -3 to +5 in compounds such as ammonia (NH3NH3), nitric acid (HNO3HNO3), nitrogen gas (N2N2), and ammonium chloride (NH4ClNH4Cl).

 

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Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Redox Reactions

Sadika

Role of Sulphur Dioxide, Hydrogen Peroxide, Ozone, and Nitric Acid as Oxidants: Sulphur dioxide (SO2SO2) and hydrogen peroxide (H2O2H2O2) can act as both oxidizing and reducing agents because they can undergo oxidation and reduction themselves. Ozone (O3O3) and nitric acid (HNO3HNO3) primarily act... read more

 

  • Role of Sulphur Dioxide, Hydrogen Peroxide, Ozone, and Nitric Acid as Oxidants:

    • Sulphur dioxide (SO2SO2) and hydrogen peroxide (H2O2H2O2) can act as both oxidizing and reducing agents because they can undergo oxidation and reduction themselves. Ozone (O3O3) and nitric acid (HNO3HNO3) primarily act as oxidants because they have high oxidation potentials and readily donate oxygen atoms or electrons to other substances.

 

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Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Redox Reactions

Sadika

Instability of AgF2 and Its Strong Oxidizing Property: AgF2 is unstable because silver typically forms compounds with a +1 oxidation state, not +2. If formed, AgF2 would have a highly positive silver ion and highly negative fluoride ions, making it an extremely unstable compound. However, if it... read more

 

  • Instability of AgF2 and Its Strong Oxidizing Property:

    • AgF2 is unstable because silver typically forms compounds with a +1 oxidation state, not +2. If formed, AgF2 would have a highly positive silver ion and highly negative fluoride ions, making it an extremely unstable compound. However, if it were to exist, AgF2 would likely act as a strong oxidizing agent because of the high electronegativity of fluorine and the high positive charge on the silver ion.

 

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