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Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > A coin is tossed. If the outcome is head , a die is...
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A coin is tossed. If the outcome is head , a die is thrown. if the die shows up an even number, the die is thrown again. what is the sample space for this experiment ?

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Case 1 With first toss if a tail turns up, the experiment stops. So getting a 'Tail' in 1st toss is one event. Case 2 Suppose it is a Head, then we throw a die. Here again the experiment will come to an end if we get an odd number on the die. 3 possibilities exists a Head and 1, a Head and...
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Case 1 With first toss if a tail turns up, the experiment stops. So getting a 'Tail' in 1st toss is one event. Case 2 Suppose it is a Head, then we throw a die. Here again the experiment will come to an end if we get an odd number on the die. 3 possibilities exists a Head and 1, a Head and 3, or a Head and 5. Case 3 After getting a head on the first toss we toss a die and this time we get an even number on a die then we throw the die again. Here we have total 18 possibilities, which are as follows: a Head and 2 and 1 a Head and 2 and 2 a Head and 2 and 3 a Head and 2 and 4 a Head and 2 and 5 a Head and 2 and 6 a Head and 4 and 1 a Head and 4 and 2 a Head and 4 and 3 a Head and 4 and 4 a Head and 4 and 5 a Head and 4 and 6 a Head and 6 and 1 a Head and 6 and 2 a Head and 6 and 3 a Head and 6 and 4 a Head and 6 and 5 a Head and 6 and 6 So total number of events = 1+3+18= 22 and the sample space is S={T,H1,H3,H5,H21,H22,H23,H24,H25,H26,H41,H42,H43,H44,H45,H46,H61,H62,H63,H64,H65,H66} read less
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SME in Mathematics & Statistics

The sample space is S = {T, H1, H3, H5, H21, H22, H23, H24, H25, H26, H41, H42, H43, H44, H45, H46, H61, H62, H63, H64, H65, H66}
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{(H,1),(H,3),(H,5),(H,2,1),(H,2,2),(H,2,3),(H,2,4),(H,2,5),(H,2,6),(H,4,1),(H,4,2),(H,4,3),(H,4,4),(H,4,5),(H,4,6),(H,6,1),(H,6,2),(H,6,3),(H,6,4),(H,6,5),(H,6,6),T } &
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Application oriented with 10 yrs exp

A coin has two faces: head (H) and tail (T). In that we need only H. A die has six faces that are numbered from 1 to 6, with one number on each face. Among these numbers, 2, 4, and 6 are even numbers, while 1, 3, and 5 are odd numbers. Here, we need only even. If it is odd, the process will be...
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A coin has two faces: head (H) and tail (T). In that we need only H. A die has six faces that are numbered from 1 to 6, with one number on each face. Among these numbers, 2, 4, and 6 are even numbers, while 1, 3, and 5 are odd numbers. Here, we need only even. If it is odd, the process will be terminated. Hence, Head along with even numbers on the die is our sample space.So, S= {H2, H4,H6} read less
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Native English Speaker with 32 years experience in teaching English and communication skills.

S={T, H1, H3, H5, H21, H22, H23, H24, H25, H26, H41, H42, H43, H44, H45, H46, H61, H62, H63, H64, H65, H66}
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Software Professional Tutor

Sample space of an experiment is the set of all possible outcomes of that experiment. When we toss coin 1st time, we can get H or T. If it is T, it's done, so one outcome is {T} If it is H, a die will be rolled and it's outcome could be 1, 2, 3, 4, 5 or 6. If it is odd (1, 3 or 6), it's done. So...
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Sample space of an experiment is the set of all possible outcomes of that experiment. When we toss coin 1st time, we can get H or T. If it is T, it's done, so one outcome is {T} If it is H, a die will be rolled and it's outcome could be 1, 2, 3, 4, 5 or 6. If it is odd (1, 3 or 6), it's done. So here outcomes are {H1, H3, H5} If it is even (2, 4 or 6), die is rolled again and it's outcome could be 1, 2, 3, 4, 5 or 6. So here outcomes are {H21, H22, H23, H24, H25, H26, H41, H24, H43, H44, H2\45, H46, H61, H62, H63, H64, H65, H66}. So sample space combination of all these, which is: {T, H1, H3, H5, H21, H22, H23, H24, H25, H26, H41, H24, H43, H44, H45, H46, H61, H62, H63, H64, H65, H66} read less
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Teaching because it is fun

This question can b solved by applying simple logical interpretation of the given question: The outcomes can be of three types: 1) Single event only (Tail is the outcome), n(single event)=1 2) Double event (Head followed by the three odd numbers on the die) n (double event) = 1 x 3= 3 3) Triple...
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This question can b solved by applying simple logical interpretation of the given question: The outcomes can be of three types: 1) Single event only (Tail is the outcome), n(single event)=1 2) Double event (Head followed by the three odd numbers on the die) n (double event) = 1 x 3= 3 3) Triple event (Head, followed by even number, followed by all the six numbers) n (triple event) 1 x 3 x 6 = 18. Therefore, n(sample space) = 22. It shouldn't be difficult to figure out the sample space from here. read less
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{T,H1,H3,H5,H21,H22,H23,H24,H25,H26,H41,H42,H43,H44,H45,H46,H61,H62,H63,H64,H65,H66}
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Matrix MATH

Think about how many ways the experiment comes to an end: 1) Toss—output=T, experiment stopped. So one outcome= T 2) Toss—output=H, next step Throw the die—output= 1 or 3 or 5, experiment stopped. So outcomes= (H,1), (H,3), (H,5). 3) Toss—output=H, next step Throw the die—output= 2 or 4 or 6, next...
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Think about how many ways the experiment comes to an end: 1) Toss—output=T, experiment stopped. So one outcome= T 2) Toss—output=H, next step Throw the die—output= 1 or 3 or 5, experiment stopped. So outcomes= (H,1), (H,3), (H,5). 3) Toss—output=H, next step Throw the die—output= 2 or 4 or 6, next throw the die again—output= 1,2,3,4,5,6. So Outcomes= (H,2, anyone from (1 to 6) ), (H,4, anyone from (1 to 6) ), (H,6, anyone from (1 to 6) ). So the required Sample Space: { (T), (H,1), (H,3), (H,5), (H,2, anyone from (1 to 6) ), (H,4, anyone from (1 to 6) ), (H,6, anyone from (1 to 6) ) } read less
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Headstart to assured 95+ score in math

T, H1 , H3, H5, H21, H23, H25, H41, H43, H45, H61, H63, H65, H221, H241, H261, H421, H441, H461, H621, H641, H661.....and so on. Make a tree and try. Hope its correct :)
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