UrbanPro

Location Set your Location

Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Book a Free Demo

Class 10 > Learn Mathematics > The adjacent sides of a rectangle are 16 cm and 8 cm....
✕

Search in

The adjacent sides of a rectangle are 16 cm and 8 cm. Find the area of the rectangle.

Asked by Last Modified  

20 Answers

Learn Mathematics +1 Class IX-X Tuition

Follow 18
Answer

Please enter your answer

Tutor

128cm^2
Comments
Dislike Bookmark

Length=16c.m Breadth=8c.m Area =l*b=16*8=128cm sq
Comments
Dislike Bookmark

Highly Qualified Tutor

Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (l × b) = (16 × 8) = (128) Area of rectangle is 128
read more

Length of the rectangle = 16 cm

Breadth of the rectangle = 8 cm

 Area of rectangle = (l × b) 

                                    = (16 × 8)

                                    = (128)

 Area of rectangle is 128 

read less
Comments
Dislike Bookmark

Tutor

Given, Length=16 cm Breadth=8cm So, Area=length × breadth =16×8=128 square cm
Comments
Dislike Bookmark

Tutor

The area of a rectangle is equal to the multiplication of two sides i.e. Area = 16*8 sq-cm = 128 sq-cm.
Comments
Dislike Bookmark

Math Magician

Length of the rectangle = 16 cm Breadth of the rectangle = 8 cm Area of rectangle = (Length × Breadth) = (16 × 8) = 128 Area of rectangle is 128
read more

Length of the rectangle = 16 cm

Breadth of the rectangle = 8 cm

 Area of rectangle = (Length × Breadth) 

                                    = (16 × 8)

                                    = 128

 Area of rectangle is 128 

read less
Comments
Dislike Bookmark

Teacher

Area = 16 x 8 = 128 sqm
Comments
Dislike Bookmark

Tutor

Area = (length*breath) = 16*8 = 128 cm^2.
Comments
Dislike Bookmark

Maths Tutor

Rectangular shape area= l×b =16×8 =128 cm^2.
Comments
Dislike Bookmark

Science Teacher

To find out the area of a rectangle you have to multiply its length with its breadth. Here, Length (L)=16 cm, and Breadth (B)=8 cm So area is, A = L*B = 16*8 = 128 sq. cm (Ans)
Comments
Dislike Bookmark

View 18 more Answers

Related Questions

How to learn math online?
Via skype you can teach everything online
Robin
The angles of a triangle are arranged in ascending order of magnitude. If the difference between two consecutive angles is 10°, find all the three angles.
Let the any one of the angle of triangle be x then other two angle are x+10, x+20 According to Question, x + (x+10) + (x+20)=180 3x + 30 = 180 3x = 150 x = 50 Thus, angles would be 50, 60, and 70.
Sradha
0 0
5
Find the area of an isoscles triangle with two equal sides as 5 cm each and the third side as 8 cm.
Let?ABC be required triangle AB=AC=5cm BC=8 cm Let AD be the altitude We know that perpendicular drawn from vertex bisect the base. Therefore BD=4 cm Using Pythagoras theorem we get AD= 3 cm Area of ?ABC=1/2...
Srinu
0 0
5
If the radius of the base of a solid cone is 'r' and its slant height is 1 then what is its lateral surface area?
Lateral surface area of cone=πrl =π×r×1 πr
Chandan
0 0
5

What parents see in a good teacher,when they hire home tutor for their child's benefit?

 
Parents must ensure the following qualities in the home tutor for their child's benefit - 1. A verified teacher- The tutor should have a valid ID proof and address proof. It ensures safety of child. 2....
Sushma

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

ABC Is An Equilateral Triangle With Side Length 6. If x Is A Point On Side CA, What Is The Minimum Value Of Bxâ² + Xcâ²?
Q. ABC is an equilateral triangle with side length 6. If X is a point on side CA , what is the minimum value of BX² + XC² ? Answer: Let's D is mid point of CA (BD = height =...

Sujoy Das

3 0
0
Solving Linear Wquation in two Varibles By Substitution Method
https://vz-3ad30922-ba4.b-cdn.net/2d534cba-73c9-4441-adee-53ec64e46332/play_480p.mp4

Nikhil Tamoli

1 0
0
NUMBER SYSTEM
NUMBER A mathematical symbol represented by a set of digits is called a number.we can express a number in two, i.e., in words & in figures.e.g., if a number is 3290, then we can write this number...
D

Deepa Thakur Sharma

2 0
1
Linear Equation in One Variable for class 9
To know the type of equations:The equation can only be solved if the number of equations is equal to the number of variables. As if the equation has two variable x and y then to find the answer of these...

Himanshu Goel

0 0
0
Ratio in its simplest form
How to convert the ratios in its simplest form ? Convert the following ratios in simplest forms, Example- a.)2:4 Choose the common number which can be used to divide both the digits in this ratio.The...
K

Kajal J.

0 0
0

Recommended Articles

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Find Class 10 Tuition near you
Class 10 Tuition in Delhi
Class 10 Tuition in Bangalore
Class 10 Tuition in Hyderabad
Class 10 Tuition in Kolkata
Class 10 Tuition in Mumbai
Class 10 Tuition in Chennai
Class 10 Tuition in Pune
Class 10 Tuition in Noida
Class 10 Tuition in Lucknow
Class 10 Tuition in Jaipur

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2024All Rights Reserved